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  • 03-10-2018
  • Mathematics
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simplify radical √m^4 n^7

answers

-mn^2 √n
-m^2n^2 √n
-m^2n^3 √n

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tramserran
tramserran tramserran
  • 03-10-2018

 [tex]\sqrt{m^{4} n^{7} }[/tex]

= [tex]\sqrt{m*m*m*m*m*N*N*N*N*N*N*N}[/tex]

Look for groups of 2 (a group of two on the inside, makes one on the outside)

= [tex]m*m*N*N*N\sqrt{N}[/tex]

= [tex]m^{2} n^{3} \sqrt{n}[/tex]

Answer: C

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