Mattymatts5342 Mattymatts5342
  • 15-03-2019
  • Mathematics
contestada

Find which term in the geometric sequence 1,3,9,27,... is the first to exceed 7,000.

Respuesta :

LammettHash
LammettHash LammettHash
  • 15-03-2019

The common ratio between terms is 3, so the sequence has general [tex]n[/tex]-th term

[tex]a_n=3^{n-1}[/tex]

for [tex]n\ge1[/tex]. The term exceeds 7000 when

[tex]3^{n-1}>7000\implies n-1>\log_37000\implies n>1+\log_37000\approx9.06[/tex]

which means the first time [tex]a_n[/tex] exceeds 7000 occurs when [tex]n=10[/tex]. Indeed,

[tex]a_{10}=3^{10-1}=19,683[/tex]

while the previous term would have been

[tex]a_9=3^{9-1}=6561[/tex]

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