nuclislath2357 nuclislath2357
  • 01-05-2019
  • Physics
contestada

Two electrodes connected to a 9.0 v battery are charged to ±45 nc. What is the capacitance of the electrode?

Respuesta :

skyluke89
skyluke89 skyluke89
  • 10-05-2019

Answer:

[tex]5\cdot 10^{-9} F[/tex]

Explanation:

The capacitance of the electrode is given by:

[tex]C=\frac{Q}{V}[/tex]

where

C is the capacitance

Q is the charge on the electrode

V is the potential difference

In this problem, we have

[tex]Q=45 nC=45\cdot 10^{-9} C[/tex]

V = 9.0 V

Substituting into the equation, we find

[tex]C=\frac{45\cdot 10^{-9}C}{9.0 V}=5\cdot 10^{-9} F[/tex] (5 nF)

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