jetblackcap jetblackcap
  • 04-06-2019
  • Mathematics
contestada

Please help me with this

Please help me with this class=

Respuesta :

jimrgrant1 jimrgrant1
  • 04-06-2019

Answer:

[tex]\frac{\sqrt{51} }{10}[/tex]

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1 ⇒ cosx = ± [tex]\sqrt{1-sin^2x}[/tex], hence

cosΘ = [tex]\sqrt{1-(7/10)^2}[/tex]

        = [tex]\sqrt{1-\frac{49}{100} }[/tex]

        = [tex]\sqrt{\frac{51}{100} }[/tex]

        = [tex]\frac{\sqrt{51} }{\sqrt{100} }[/tex] = [tex]\frac{\sqrt{51} }{10}[/tex]

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