RaeStudies RaeStudies
  • 05-08-2019
  • Physics
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I have a question and no one has helped me yet so I'm re-submitting it. thanks in advance. ​

I have a question and no one has helped me yet so Im resubmitting it thanks in advance class=

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rokettojanpu
rokettojanpu rokettojanpu
  • 05-08-2019

Apply this kinematics equation for the particle's vertical motion:

D = Vt + 0.5At²

D = vertical distance traveled, t = time, V = initial vertical velocity, A = vertical acceleration

Given values:

D = 49m

V = 34.3m/s

A = -9.81m/s²

Plug in and solve for t:

49 = 34.3t - 4.905t²

4.905t² - 34.3t + 49 = 0

Use the quadratic roots formula to find the values of t:

t ≈ 2, 5

The particle reaches a height of 49m at t = 2s & t = 5s

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