c7068641 c7068641
  • 02-11-2019
  • Mathematics
contestada

SA=4pir^2

Solve for r

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jdoe0001 jdoe0001
  • 02-11-2019

[tex]\bf \textit{surface area of an sphere}\\\\ SA=4\pi r^2\implies \cfrac{SA}{4\pi }=r^2\implies \sqrt{\cfrac{SA}{4\pi }}=r[/tex]

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