dreamakadie4691 dreamakadie4691
  • 02-01-2020
  • Chemistry
contestada

Write the Ksp expression for the sparingly soluble compound calcium phosphate, Ca3(PO4)2.

Respuesta :

dvynnjoku dvynnjoku
  • 03-01-2020

Answer:

Ksp = 1.3 x 10^(-32) = (3s)^(3) x (2s)^(2)

= 27s^(3) x 4s^(2) = 108s^(5)

Explanation:

Ca3(PO4)2(s) 3Ca^(2+)(aq) + 2PO4^(3-)(aq)

[Ca^(2+)] = 3 [Ca3(PO4)2] = 3s

[PO4^(3-)] = 2 [Ca3(PO4)2] = 2s

Ksp = 1.3 x 10^(-32) =[Ca^(2+)]^(3)×[PO4^(3-)]^(2)

Ksp = 1.3 x 10^(-32) = (3s)^(3) x (2s)^(2)

= 27s^(3) x 4s^(2) = 108s^(5)

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