jkplant4792 jkplant4792
  • 16-01-2020
  • Physics
contestada

If the monthly electricity consumption of a household is 6,619 kWh, what is this consumption expressed in kJ

Respuesta :

sebasacevedop
sebasacevedop sebasacevedop
  • 16-01-2020

Answer:

[tex]2.38*10^{4}kJ[/tex]

Explanation:

One watt equals to 1 joule per second. So, one kilowatt equals 1 kilojoule per second. Thus, one kilowatt-hour is equivalent to:

[tex]1kWh=1\frac{kJ}{s}*3600s=3600kJ[/tex]

Finally, we can calculate the monthly electricity consumption in kJ:

[tex]6,619kWh*\frac{3600kJ}{1kWh}=2.38*10^{4}kJ[/tex]

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