SavgeKid6312 SavgeKid6312
  • 16-01-2020
  • Mathematics
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4) In how many different ways can four people be put into three subsets containing two people, one person, and one person?

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LammettHash
LammettHash LammettHash
  • 16-01-2020

Assuming order doesn't matter:

From the total 4 people, you choose 2 - this is [tex]\binom42=6[/tex].

From the remaining 2 people, you choose 1 - this is [tex]\binom21=2[/tex].

From the last person, you choose that person - this is [tex]\binom11=1[/tex]

So there are 6*2*1 = 12 possible ways.

Note: [tex]\binom ab=\frac{a!}{b!(a-b)!}[/tex] is the binomial coefficient

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