conmor900 conmor900
  • 04-03-2020
  • Mathematics
contestada

5x^2+ 23x + 12
Factoring ​

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 12-03-2020

Answer:

[tex](5 x+ 3)(x + 4)[/tex]

Step-by-step explanation:

We want to factor

[tex]5 {x}^{2} + 23x + 12[/tex]

By comparing to

[tex]a {x}^{2} + bx + c[/tex]

We have a=5, b=23, c=12

ac=60

We split the middle term with 3x+20x, since 3×20=60

This implies that:

[tex]5 {x}^{2} + 3x + 20x + 12[/tex]

Factor by grouping;

[tex]x(5 x+ 3)+ 4(5x + 3)[/tex]

We collect common factors again;

[tex](5 x+ 3)(x + 4)[/tex]

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