jackievelasquez8412 jackievelasquez8412
  • 04-03-2020
  • Physics
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The coefficient of performance of a residential heat pump is 1.6. Calculate the heating effect in kJ/s this heat pump will produce when it consumes 4 kW of electrical power.

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Khoso123
Khoso123 Khoso123
  • 09-03-2020

Answer:

[tex]Q_{H}=6.4kJ/s[/tex]

Explanation:

Given data

Coefficient of performance of a residential heat pump=1.6

Electrical power P=4kW

Required

Heat Q

Solution

The rate of heat produced is given as

[tex]Q_{H}=COP_{HP}Win\\[/tex]

Substitute the given values

So

[tex]Q_{H}=4kW*1.6\\Q_{H}=6.4kJ/s[/tex]

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