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How many grams of calcium nitrate are needed to make a 3.30 L of a 0.10 M solution?

Respuesta :

mneedsanswers
21.1 grams
molarity=moles of the solute/volume of the solute
.1M=x/3.3L
x=.1M • 3.3L= 3.3 Mol
molar mass of calcium nitrate is 164.088 g/mol
the mass of .33 mol of calcium nitrate is 21.1

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