cameroncarstarphen01 cameroncarstarphen01
  • 02-04-2020
  • Mathematics
contestada

A cliff diver strikes the water with a velocity of 32 square root 5 feet per second. Find the height which the diver dove. V=square root 2gh

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instaoceanclash
instaoceanclash instaoceanclash
  • 02-04-2020

Answer:

80

Step-by-step explanation:

equation [tex]v=\sqrt{2gh}[/tex]

v = [tex]32\sqrt{5}[/tex] feet/s

g = 32 feet/s^2

plug in values

[tex]32\sqrt{5}[/tex] = [tex]\sqrt{2*32*h}[/tex]

[tex]\sqrt{32^{2}} * \sqrt{5} = \sqrt{32^{2}*5} = \sqrt{2*32*h}[/tex]

[tex]32^2 * 5 = 2 * 32 * h[/tex]

32 * 5 = 2h

h = 32 * 5 / 2

h = 80

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