megsxo80 megsxo80
  • 03-04-2020
  • Mathematics
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Principal value of Arccos(-1)

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DeanR
DeanR DeanR
  • 03-04-2020

You may have wondered what Euler's Identity means

[tex]e^{i \pi} = -1[/tex]

I hate to break it to you but it just means

[tex]\cos \pi + i \sin \pi = -1 + 0i[/tex]

Equating respective real and imaginary parts,

[tex]\cos \pi = -1, \qquad \sin \pi = 0[/tex]

which you probably already knew.

From the first part,

[tex]\pi = \arccos(-1)[/tex]

That's in the principal value range of cosine.

[tex]\pi = \textrm{Arccos}(-1)[/tex]

Answer: π

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