serinasantiago
serinasantiago serinasantiago
  • 01-05-2020
  • Mathematics
contestada

only answer if yk the answer giving correct answer brainliest !


Solve the equation for all real solutions in simplest form:
4n^2-19n+18=0

Respuesta :

valeryswilliams
valeryswilliams valeryswilliams
  • 01-05-2020

Answer:

n=3.4, n=1.3

Step-by-step explanation:

4n^2-19n+18=0

solve using quadratic formula

a=4, b=-19, c=18

n=-(-19)±√(-19)^2-4·4·18/2·4

(solve using calulator or PEMDAS)

(solve for both + and -)

n=3.4, n=1.3

Answer Link

Otras preguntas

How might a theory relate to a model in science?
What is 0.003is 1/10 of
the difference between the square roots of a number is 30. What is the number?
what is V=LWH for L?
what is the names for plants that survive a major disturbance?
how do you write 35.2 in word form?
who can help me with quantitative observation examples
What is the estimate for 403,446+396,755 help please
Help me solve this:5 hundreds x 10 = ________ hundreds= ______
36/b-3=0 find the solution of this equation.