alexusneal911
alexusneal911 alexusneal911
  • 04-05-2020
  • Mathematics
contestada

What is the center of the circle given by the equation (x-3)2 + (y-9)2 = 16?
A. (-9,-3)
B. (-3,-9)
C. (3,9)
D. (9,3)

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 04-05-2020

Answer:

The center is (3,9) and the radius is 4

Step-by-step explanation:

We can write the equation for a circle as

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-3)^2 + (y-9)^2 = 4^2

The center is (3,9) and the radius is 4

Answer Link
TREKKER
TREKKER TREKKER
  • 04-05-2020

Answer:

C

Step-by-step explanation:

(x-a)^2 + (y-b)^2 = r^2

(a,b) = Center

r = radius

SO...

That means the center of the circle " (x-3)^2 + (y-9)^2 = 16" is...

(3,9) (C)

Answer Link

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