Answer:
[tex]\Delta _mS=7.63\frac{J}{mol*K}[/tex]
Explanation:
Hello,
In this case the entropy of fusion is associated with the enthalpy and the temperature when a solid goes liquid and takes the form:
[tex]\Delta _mS=\frac{\Delta _mH}{T}[/tex]
Whereas the temperature must be in absolute Kelvins:
[tex]\Delta _mS=\frac{13.8kJ/mol}{(1535+273.15)K}*\frac{1000J}{1kJ} \\\\\Delta _mS=7.63\frac{J}{mol*K}[/tex]
Best regards.
