sjpalomino4002 sjpalomino4002
  • 13-05-2020
  • Mathematics
contestada

What are the possible values of x if (4x-5)2=49

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 13-05-2020

Answer:

3, -1/2

Step-by-step explanation:

(4x-5)^2=49

Take the square root of each side

sqrt(4x-5)^2=±sqrt(49)

4x-5 = ±7

Add 5 to each side

4x-5+5 =5 ±7

4x = 5 ±7

Divide each side by 4

4x/4 = (5 ±7)/4

x = (5 ±7)/4

Solve for the positive

x =(5+7)/4 = 12/4 =3

Now the negative

x = (5-7)/2 = -2/4 = -1/2

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