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  • 13-05-2020
  • Chemistry
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Calculate the heat energy absorbed or released to evaporate 6g of liquid water.

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xero099
xero099 xero099
  • 19-05-2020

Answer:

[tex]Q_{net} = 15469.5\,J[/tex]

Explanation:

Let assume that liquid water has an initial temperature of 25°C and heating and evaporation process occurs under a pressure of 1 atmosphere. Then, the heat absorbed is equal to the sum of sensible and latent components:

[tex]Q_{net} = Q_{s} + Q_{l}[/tex]

[tex]Q_{net} = (6\,g)\cdot \left[\left(4.186\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (100\,^{\circ}C-25\,^{\circ}C)+2264.3\,\frac{J}{g} \right][/tex]

[tex]Q_{net} = 15469.5\,J[/tex]

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