Answer:
(-∞, 0)
Step-by-step explanation:
Given
u(x) = -2x^2
v(x) = 1/x
Find
The range of (u◦v)(x)
Solution
(u◦v)(x) = u(v(x)) = u(1/x) = -2(-1/x)^2 = -2/x^2
The denominator is always positive (since x=0 is excluded from the domain), so the fraction is always negative. There is a horizontal asymptote at y=0. The range is ...
(-∞, 0)
