Answer:
[tex]Ksp=[Ag^+]^2[(CO_3)^{-2}][/tex]
Explanation:
Hello,
In this case, we should start by writing the equilibrium dissociation of silver carbonate as:
[tex]Ag_2CO_3(s)\rightleftharpoons 2Ag^+(aq)+(CO_3)^{-2}(aq)[/tex]
In such a way, by means of the law of mass action for heterogeneous equilibrium (as silver carbonate is solid), we represent the solubility product expression as shown below:
[tex]Ksp=[Ag^+]^2[(CO_3)^{-2}][/tex]
Best regards.
