dalaneyhaines dalaneyhaines
  • 14-05-2020
  • Mathematics
contestada

What's the vertex of the following equation X^2- 10x + 25

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 14-05-2020

Answer:

(5,0)

Step-by-step explanation:

X^2- 10x + 25

The vertex is at

h = -b/2a  where  ax^2 +bx +c

b = -10 and a =1

h = -(-10)/2(1)

  = 10/2 = 5

The vertex is at x=5

To find the y value stick x=5 into the function

5^2 -10(5) +25

25-50+25 = 0

The vertex is at 5,0

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priscilla1108
priscilla1108 priscilla1108
  • 14-05-2020
It would be (5,0) !!
Answer Link

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