jthompson6566
jthompson6566 jthompson6566
  • 01-06-2020
  • Mathematics
contestada

write the equation of a line perpendicular to y=3x-2 through the point (-5,8).

Respuesta :

thisis4trashlikeu thisis4trashlikeu
  • 01-06-2020

Answer:

y=-1/3x +29/3

Step-by-step explanation

We know that the line perpendicular to a slope of 3 is it's opposite reciprocal. So the slope is -1/3. Substitute -5 as X and 8 as Y so you get:

8= -5/3x +b.

B= 29/3

That's your answer.

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