sparky77 sparky77
  • 02-06-2020
  • Mathematics
contestada

For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?

Respuesta :

jajumonac jajumonac
  • 07-06-2020

Answer:

[tex]k=0[/tex] and [tex]k=3[/tex].

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of [tex]k[/tex] that makes those coordinates equal.

[tex]k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0\\[/tex]

Using the null factor property, we have

[tex]k=0\\k-3=0 \implies k=3[/tex]

Therefore, the given relation is not a function when [tex]k=0[/tex] and [tex]k=3[/tex].

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