sleep2160 sleep2160
  • 04-06-2020
  • Mathematics
contestada

Find the area A of △JKL with vertices J(−4,10), K(0,3), and L(−4,−2).

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profantoniofonte
profantoniofonte profantoniofonte
  • 10-06-2020

Answer:

24 sq. u.

Step-by-step explanation:

1)For this triangle area, let's use the classic Euclidean formula:

[tex]\Delta \: area=\frac{b*h}{2}[/tex]

2) Let's measure the lenght of the base, taking the y coordinate of J vertex and L Vertex

[tex]|10-(-2)|=|12|=12[/tex]

3) Similarly to the height, taking the K and its distance to the base

|0-(-4)|=|4|=4

4) Plugging them in:

[tex]\Delta \: area=\frac{12*4}{2}=24[/tex]

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Answer Link
2408439 2408439
  • 22-09-2021

Answer:

24 Square Units

Step-by-step explanation:

Answer Link

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