1096175 1096175

02-08-2020
Mathematics

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$i^{11} + i^{16} + i^{21} + i^{26} + i^{31}$[tex]$i^{11} + i^{16} + i^{21} + i^{26} + i^{31}$[/tex]

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surjithayer10 surjithayer10

02-08-2020

Answer:

Step-by-step explanation:

i^{11}+i^{16}+i^{21}+i^{26}+i^{31}

[tex]=(i^{2} )^5i+(i^{2} )^8 +(i^{2} )^{10} i+(i^{2} )^{13}+(i^{2} )^{15} i\\=(-1)^5 i+(-1)^8+(-1)^{10} i+(-1)^{13} +(-1)^{15} i\\=- i+1+i-1-i\\=0- i[/tex]

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