brooklyncaddie13 brooklyncaddie13
  • 04-08-2020
  • Mathematics
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The equation of C is (x - 2)^2 + (y - 1)^2 = 25. Of the points P(0,5), Q(2,2) R(5,-2), and S(6,6), which point is located outside the circle?

The equation of C is x 22 y 12 25 Of the points P05 Q22 R52 and S66 which point is located outside the circle class=

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 04-08-2020

Answer:

( 6,6) is outside

Step-by-step explanation:

(x - 2)^2 + (y - 1)^2 = 25

This is of the form

(x - h)^2 + (y - k)^2 = r^2

where ( h,k) is the center and r is the radius

(x - 2)^2 + (y - 1)^2 = 5^2

The center is at ( 2,1) and the radius is 5

P(0,5), Q(2,2) R(5,-2), and S(6,6)

Adding the radius to the y coordinate gives us 6 so the only point with a y coordinate on the circle is ( 2,6)

( 6,6) is outside the circle

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