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  • 04-08-2020
  • Mathematics
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e[tex]e^{x} - e^{-2} =-2[/tex]

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Аноним Аноним
  • 10-08-2020

$e\cdot e^x -e^{-2}=-2$

$\implies e^{x+1}=e^{-2}-2$

note that RHS is negative. (because e with negative exponent is less than 1)

and LHS is always positive.

so there cannot be any solution

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