Given :
Length of parade , [tex]L = 3\ miles=3\times 5280\ miles = 15840\ miles[/tex] .
Breadth of parade , [tex]B=2\times 15=30\ ft[/tex] .
5 people can fit into a [tex]25\ ft^2[/tex] area.
1 mile = 5280 ft .
To Find :
The size of the crowd.
Solution :
Area of parade ,
[tex]A=15840\times 30\ ft^2\\\\A=475200\ ft^2[/tex]
Also , 5 people can fit in [tex]25\ ft^2[/tex] area .
So , number of people fit in A is :
[tex]n = \dfrac{475200\times 5}{25}\\\\n=95040[/tex]
Therefore , 95040 can fit in the parade .
Hence , this the required solution .
