sydneystfleur12
sydneystfleur12 sydneystfleur12
  • 02-11-2020
  • Mathematics
contestada

HELP ASAP PLEASE AND SHOW WORK!!!
Write the vertex form of the following equation. y= x^2+6x-5

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unicorn3125
unicorn3125 unicorn3125
  • 03-11-2020

Answer:

           [tex]\boxed{\bold{y=(x+3)^2-14}}[/tex]

Step-by-step explanation:

y= x²+6x-5

completing the square:  a²+2ab+b² = (a+b)²  where a²=x² (so a=x) and 2ab=6x (so b would be 3):

[tex]y=x^2+6x-5\\\\y=\underline{x^2+2\cdot x\cdot3+3^2}-3^2-5\\\\y=(x+3)^2-9-5\\\\\underline{y=(x+3)^2-14}\\\\\\vertex:\ \ (-3,\,-14)[/tex]

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