Iamlolol
Iamlolol Iamlolol
  • 02-11-2020
  • Mathematics
contestada

Can any kind soul help me​

Can any kind soul help me class=

Respuesta :

Lightning25346
Lightning25346 Lightning25346
  • 02-11-2020

Answer:

x(x-2) = 5

=> x^2 -2x-5 = 0

a=1, b= -2, c= -5

Discriminant= b^2-4ac

= (-2)^2 - 4(1)(-5)

=4+20

=24

Since Discriminant > 0

Therefore the roots are real and distinct.

Hope it helps....... mark me as brainliest

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kithu13
kithu13 kithu13
  • 02-11-2020

[tex]x(x - 2) = 5 \\ {x}^{2} - 2x = 5 \\ {x}^{2} - 2x + 1 = 5 + 1 \\ {(x - 1)}^{2} = 6 \\ x - 1 = \sqrt{6} \\ x = 1 + \sqrt{6} [/tex]

... Hope this will help...

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