ItsPandini
ItsPandini ItsPandini
  • 01-10-2016
  • Mathematics
contestada

Consider the function F(x)=x^3-6x^2+9x. What are the x-intercepts of F(x)? write the soltuin(s) as ordered pairs.

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bearbedell
bearbedell bearbedell
  • 01-10-2016
(x^3-6x+9x)/x = x(x^2+6x+9)

(x)(x^2+6x+9)          x-3=0        x=0
 (x)(x-3)(x-3)             +3 +3

(3,0) (0,0)
Answer Link
apologiabiology
apologiabiology apologiabiology
  • 01-10-2016
x intercepts are the roots (remember that y=0 at x intercepts)
for roots r1 and r2, the factors are (x-r1) and (x-r2)

factor

f(x)=x^3-6x^2+9x
factour out x
f(x)=(x)(x^2-6x+9)
factor
f(x)=(x)(x-3)(x-3)
f(x)=(x-0)(x-3)(x-3)

the x intercepts are at x=0, and at x=3

solutions are
(0,0) and (3,0)
Answer Link

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