lovegodest1 lovegodest1
  • 03-12-2020
  • Mathematics
contestada

#3, #19, and #16 please!!

3 19 and 16 please class=
3 19 and 16 please class=
3 19 and 16 please class=

Respuesta :

inspire123andcreate
inspire123andcreate inspire123andcreate
  • 03-12-2020
To answer number 3 all you have to do is put 15 times x <_ 12 (put a line directly underneath the sign)

To answer number 19, do 21-11= 10 This means that X=10

X(10) plus 11=21

21=21

[10 + 11] >_ 21


To solve 16.

Add 3 to 13 to get 16

Then you’ll have [3x +4] >_ 16

Once you have this, subtract 4 from both sides.

Then you’ll have 3x>_ 12

Now you can divide each side by 3 to get x>_4. X=4

So if we plug that in [3x +4] >_ 13, you’ll get

[3(4) +4] >_ 13

And then you’ll get

[16] >_ 13


I hope this helps!!
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