kaikoala05
kaikoala05 kaikoala05
  • 03-02-2021
  • Mathematics
contestada

If ANQZ - ACBK, find BK. *

O BK = 39
O BK = 16
O BK = 65
O BK = 27
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If ANQZ ACBK find BK O BK 39O BK 16O BK 65O BK 27 class=

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 04-02-2021

9514 1404 393

Answer:

  (c)  BK = 65

Step-by-step explanation:

Corresponding sides are proportional in similar triangles, so ...

  ZT/ZQ = KF/KB

  27/(2x +7) = 45/(4x+1)

  27(4x+1) = 45(2x +7) . . . cross-multiply

  3(4x +1) = 5(2x +7) . . . . divide by 9

  12x +3 = 10x +35 . . . . . eliminate parentheses

  2x = 32 . . . . . . . . . . . . . subtract 10x+3

  x = 16 . . . . . divide by 2

Then the length of BK is ...

  BK = 4x+1 = 4·16 +1

  BK = 65

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