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01-03-2021
Chemistry

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Calculate the volume in liters of a 0.72 M aluminum sulfate solution that contains 75.0 g of aluminum sulfate Al2SO43.

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03-03-2021

Answer:

0.30 L

Explanation:

First we convert 75.0 g of Al₂(SO₄)₃ into moles, using its molar mass:

75.0 g ÷ 342.15 g/mol = 0.219 mol Al₂(SO₄)₃

Then we can calculate the volume of the solution, by using the definition of molarity:

Molarity = moles of solute / liters of solution

0.72 M = 0.219 mol / Volume

We solve for Volume:

Volume = 0.30 L

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