hamidaa3 hamidaa3

04-05-2021
Mathematics

contestada

T(z)= sin^2(z/4), {-3 ≤ z ≤ 8}

Respuesta :

ethannewton59 ethannewton59

04-05-2021

Answer:

T´(z)=n^2s/4*i

Step-by-step explanation:

T(z)=d/dz(sin^2*z/4)

T´(z)=d/dz(sn^2zi/4)

T´(z)=d/dz(sn^2z/4*i)

T´(z)i*d/dz(sn^2z/4)

T´(z)=n^2s/4*i

Simplify

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