Seudónimo Seudónimo
  • 02-09-2021
  • Mathematics
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Can anyone help me with this, please?

Can anyone help me with this please class=

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 04-09-2021

9514 1404 393

Answer:

  C.  3x∛(y²z)

Step-by-step explanation:

The relevant rules of exponents are ...

  [tex]\sqrt[n]{a^m} = a^\frac{m}{n}\\\\(a^b)^c=a^{bc}[/tex]

__

Your expression can be rewritten and simplified as follows.

  [tex]\displaystyle\sqrt[3]{27x^3y^2z}=(3^3x^3y^2z)^\frac{1}{3}=3xy^\frac{2}{3}z^\frac{1}{3}=3x(y^2z)^\frac{1}{3}=\boxed{3x\sqrt[3]{y^2z}}[/tex]

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