asalehi35 asalehi35
  • 03-12-2021
  • Mathematics
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Please help with this problem

Please help with this problem class=

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sqdancefan
sqdancefan sqdancefan
  • 05-12-2021

Answer:

  (d)  ∞

Step-by-step explanation:

The expression can be simplified to one that is not indeterminate:

  [tex]\dfrac{(1+x)^{24}}{x}-\dfrac{1}{x}=\dfrac{(1+x)^{24}-1}{x}=\dfrac{1+24x+\dots+24x^{23}+x^{24}-1}{x}\\\\=\dfrac{24x+\dots+24x^{23}+x^{24}}{x}\\\\=24+\dots+24x^{22}+x^{23}[/tex]

A polynomial with a positive leading coefficient will tend to infinity as x goes to infinity.

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