javanelder05
javanelder05 javanelder05
  • 04-05-2022
  • Mathematics
contestada

find the equation of circle (5,1) diameter 4 square root 5​

Respuesta :

semsee45
semsee45 semsee45
  • 04-05-2022

Answer:

[tex](x-5)^2+(y-1)^2=20[/tex]

Step-by-step explanation:

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

(where (a, b) is the center and r is the radius)

Given:

  • center = (5, 1)
  • diameter = 4√5

Diameter = 2r (where r is the radius)

⇒ r = 4√5 ÷ 2 = 2√5

Substituting these values into the equation:

[tex]\implies (x-5)^2+(y-1)^2=(2\sqrt{5})^2[/tex]

[tex]\implies (x-5)^2+(y-1)^2=20[/tex]

Answer Link

Otras preguntas

A car traveling in a straight line has a velocity of 3.79 m/s at some instant. After 5.4 s, its velocity is 11.9 m/s. What is its average acceleration in this t
How can the fiscal policies of a country influence individual finances?
what is the nearest hundred of 403.12
What is meant by the "partition" of India in 1947?
Write −(−2z − 5y) in simplified form.
What is 1,537 x 242?
What were the two main areas of dispute between Russia and Japan during the Russo-Japanese War? Korea Manchuria China Siberia
An amoeba eats some food. Which organelles will help store and digest it? vacuoles and lysosomes mitochondria and ribosome endoplasmic reticulum and the Golgi a
If p=5 what is the value of 6p-4?
A fern grows sporangia under its fronds. What is the next step in its life cycle?