dbjkf4202 dbjkf4202
  • 14-05-2022
  • Mathematics
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5-16 find the general indefinite integral.
8. [tex]\int\left(u^{6}-2 u^{5}-u^{3}+\frac{2}{7}\right) d u[/tex]

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jdoe0001 jdoe0001
  • 14-05-2022

[tex]\displaystyle\int \left( u^6 - 2u^5 - u^3 + \cfrac{2}{7} \right)du\implies \cfrac{u^7}{7}-2\cdot \cfrac{u^6}{6}-\cfrac{u^4}{4}+\cfrac{2}{7}u \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{u^7}{7}- \cfrac{u^6}{3}-\cfrac{u^4}{4}+\cfrac{2u}{7}+C~\hfill[/tex]

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