The slope of the line is m=2/3.
The line passes through the point (x1, y1)=(2, -5).
The point slope form of the equation of line is,
[tex]\begin{gathered} \frac{2}{3}=\frac{y1-y}{x1-x} \\ \frac{2}{3}=\frac{-5-y}{2-x} \\ 2(2-x)=3(-5-y) \\ 4-2x=-15-3y \\ 3y=2x-15-4 \\ 3y=2x-19 \\ y=\frac{2}{3}x-\frac{19}{3} \end{gathered}[/tex]The graph of the line can be plotted as,
