LiamZ773192 LiamZ773192
  • 03-11-2022
  • Mathematics
contestada

please help me ASAP!!!

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KarizmaS317346 KarizmaS317346
  • 03-11-2022
[tex]\begin{gathered} f(x)=\sqrt[]{2x^2-3x+1} \\ x=5 \\ f(5)=\sqrt[]{2(5^2)-3(5)+1} \\ f(5)=\sqrt[]{36} \\ f(5)=6 \end{gathered}[/tex]

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