AlysiannaT286674 AlysiannaT286674
  • 03-11-2022
  • Mathematics
contestada

how to solve 2(q+4)=16how to solve 7j+2=12+5jhow to solve 12z=60-3z

Respuesta :

JaneeD413954 JaneeD413954
  • 03-11-2022

Answer:

Given that to solve

a) 2(q+4)=16

we get,

[tex]\begin{gathered} 2\mleft(q+4\mright)=16 \\ 2q+8=16 \end{gathered}[/tex][tex]2q=16-8[/tex][tex]2q=8[/tex]

Dividing 2 on both sides we get,

[tex]q=4[/tex]

Answer is: q=4

b)7j+2=12+5j

we get,

[tex]7j+2=12+5j[/tex][tex]7j-5j=12-2[/tex][tex]2j=10[/tex]

Dividing 2 on both sides, we get

[tex]j=10[/tex]

c) 12z=60-3z

we get,

[tex]12z=60-3z[/tex][tex]12z+3z=60[/tex][tex]15z=60[/tex]

Dividing 15 on both sides we get,

[tex]z=4[/tex]

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