MaelynP784173 MaelynP784173
  • 03-11-2022
  • Mathematics
contestada

can you break it down and help me out please?

can you break it down and help me out please class=

Respuesta :

DamionE702188 DamionE702188
  • 03-11-2022

Given

[tex]x^2+x-2\ge0[/tex]

To find the solution.

Now,

It is given that,

[tex]x^2+x-2\ge0[/tex]

Using factorization method,

[tex]\begin{gathered} x^2+x-2=0 \\ x^2-x+2x-2=0 \\ x(x-1)+2(x-1)=0 \\ (x+2)(x-1)=0 \end{gathered}[/tex]

That implies,

[tex]\begin{gathered} x+2\ge0,x-1\ge0 \\ x\ge-2,x\ge1 \end{gathered}[/tex]

Hence, the solution set is,

[tex]undefined[/tex]

Answer Link

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