chelseatalent12
chelseatalent12 chelseatalent12
  • 01-04-2017
  • Chemistry
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How many grams of solid baso4 will form when ba2so4 react with 25mL of .50 M Ba(NO3)2

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vanhkhuyentt2
vanhkhuyentt2 vanhkhuyentt2
  • 01-04-2017
Na2SO4+ Ba(NO3)2 --> 2NaNO3 + BaSO4
                    0.0125                            0.0125
mole of Ba(NO3)2 = 0.025 * 0.5 = 0.0125 (mole) 
The grams of BaSO4 = 0.0125 * ( 137+32+16*4) = 2.9125(g)
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