georgie00
georgie00
02-07-2017
Mathematics
contestada
Could I have help to find x?
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konrad509
konrad509
02-07-2017
[tex]\dfrac{16^{x+1}}{8^{2x+2}}=16\\ \dfrac{2^{4x+4}}{2^{6x+6}}=2^4\\ 2^{4x+4-6x-6}=2^4\\ 2^{-2x-2}=2^4\\ -2x-2=4\\ -2x=6\\ x=-3 [/tex]
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Banabanana
Banabanana
02-07-2017
[tex] \cfrac{16^{x+1}}{8^{2x+2}}=16 \\ \\ \cfrac{(2^4)^{x+1}}{(2^3)^{2x+2}}=2^4 \\ \\ \cfrac{2^{4x+4}}{2^{6x+6}}=2^4 \\ \\ 2^{4x+4-(6x+6)}=2^4 \\ 2^{4x+4-6x-6}=2^4 \\ 2^{-2x-2}=2^4\\ \\ -2x-2=4 \\ -2x = 4+2 \\ -2x=6 \\ 2x=-6 \\ x=-6/2 \\ x=-3[/tex]
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