alicekim020705 alicekim020705
  • 03-10-2017
  • Mathematics
contestada

a line has a slope of -2/3 and passes through the point -3, 8 what is the equation of the line

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abelsull8411
abelsull8411 abelsull8411
  • 05-10-2017
y= -2/3 +6   bc...
(-3,8)
 y=mx+b
 8= -2/3(-3) +b
 8=2+b
-2 -2
6=b

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SociometricStar
SociometricStar SociometricStar
  • 16-08-2019

Answer:

[tex]y=-\frac{2}{3}x+6[/tex]

Step-by-step explanation:

we have been give  that

slope, m = -2/3

The line passes through the point (-3,8).

Hence, [tex]x_1=-3,y_1=8[/tex]

The point slope form of a line is

[tex]y-y_1=m(x-x_1)[/tex]

Substituting the known values

[tex]y-8=-\frac{2}{3}(x-(-3))[/tex]

On simplifying, we get

[tex]y-8=-\frac{2}{3}x-2\\\\y=-\frac{2}{3}x+6[/tex]

Thus, equation of line is [tex]y=-\frac{2}{3}x+6[/tex]

Answer Link

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