What is the hydronium ion concentration of a 0.500 m acetic acid solution with ka = 1.8 × 10-5? the equation for the dissociation of acetic acid is:?

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03-12-2017
Chemistry

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What is the hydronium ion concentration of a 0.500 m acetic acid solution with ka = 1.8 × 10-5? the equation for the dissociation of acetic acid is:?

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W0lf93 W0lf93 · Answer 1 · 2017-12-15T21:34:41+01:00

W0lf93 W0lf93

15-12-2017

The equation for the dissociation of acetic acid is:
CH3CO2H(aq) + H2O(l) <---> H3O+(aq) + CH3CO2-(aq)
pH = 0.5(4.74 - lg(0.5)) = 2.52
so
[H^+] = 3.02*10^-3 M = 3.02 mM

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