MiladTaher MiladTaher
  • 02-01-2018
  • Mathematics
contestada

Find the equation of the line that contains the point (6,-2) and is perpendicular to the line y=-2⁢x+8 .

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texaschic101
texaschic101 texaschic101
  • 02-01-2018
y = -2x + 8. The slope here is -2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal slope, we flip the original slope and change the sign. So we have -2 or -2/1.....flip it and it becomes -1/2....change the sign and it becomes 1/2. So our perpendicular line will have a slope of 1/2.

y = mx + b
slope(m) = 1/2
(6,-2)....x = 6 and y = -2
now we sub and find b, the y int
-2 = 1/2(6) + b
-2 = 3 + b
-2 - 3 = b
-5 = b
so ur perpendicular equation is : y = 1/2x - 5 <===
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