joannegrace5731 joannegrace5731
  • 03-01-2018
  • Mathematics
contestada

Help with homework Algebra 2:
What is the quotient (72y3 + 12y2 − 30y) ÷ 6y?

12y2 − 2y + 5
12y2 + 2y − 5
12y3 + 2y2 − 5y
12y2 − 2y − 5

Respuesta :

gandomlk00
gandomlk00 gandomlk00
  • 03-01-2018
The answer is 12y^2 + 2y - 5
The solution:
(72y^3 + 12y^2 - 30y) / 6y =
(6y)*(12y^2 + 2y - 5) / 6y = 12y^2 + 2y - 5
Answer Link
lisboa lisboa
  • 24-06-2019

Answer:

[tex]12y^2+2y-5[/tex]

Step-by-step explanation:

[tex](72y^3 + 12y^2 - 30y)[/tex] ÷ 6y

WE divide each term by 6y, while dividing by 6y we apply property of exponent

a^m / a^n= a^m-n

[tex]\frac{72y^3}{6y} =12y^2[/tex]

[tex]\frac{12y^2}{6y} =2y[/tex]

[tex]\frac{30y}{6y} =5[/tex]

Now we combine all the terms

[tex]12y^2+2y-5[/tex]

Answer Link

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